The equilibrium constant for a reaction is K, and the reaction quotient is Q . For a particular reaction mixture , the ration `(K)/(Q)` is 0.33. this means that:
A
the reaction mixture will equilirate to from more reactant species
B
the rection mixture will equilirate to from more product species
C
the equlibrium ratio of reactant to product concentration will be 3
D
the equilibrium ratio of reactant to product concentrations will be 0.33
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
The equilibrium constant of a chemical reaction
The reaction Quotient (Q) predicts:
At 300 K, the equilibrium constant for a reaction is 10. the standard free energy change (in kJ mol^(-1) ) for the reaction is
The equilibrium constant (K_(C)) for the reaction HA +B hArr BH^(+) + A is 100. If the rate constant for the forward reaction is 10^(5) , rate constant for the reverse reaction is
When two reactants A and B are mixed to give products C and D, the reaction quotient (Q) at the intiai stages of the reaction:
The graph relates in K_(eq) Vs 1/T for a reaction. The reaction must be :
The rate constant of a reaction is doubled when the temperature is raised from 298 K to 308 K. Calculate the activation energy.
