Home
Class 11
CHEMISTRY
For the reaction H(2)(g)+I(2)(g)hArr2HI(...

For the reaction `H_(2)(g)+I_(2)(g)hArr2HI(g)`
the equilibrium constant `K_(p)` changes with

A

total pressure

B

catalyst

C

concentration of`H_(2)and I_(2)`

D

temperature

Text Solution

Verified by Experts

The correct Answer is:
d
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos

  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

If the equilibrium constant for the reaction, H_(2)(g) +I_(2)(g) hArr 2HI(g) is K What is the equilibrium constant of HI(g) rarr 1/2 H_(2)(g) + 1/2I_(2)(g) ?

The equilibrium constant for the given reaction is 100. N_(2)(g) + 2O_(2)(g) hArr 2NO_(2)(g) What is the equilibrium constant for the reaction given below? NO_(2)(g) hArr 1/2 N_(2)(g) + O_(2)

In the reaction H_(2)(g) + Cl_(2) (g) rarr 2HCI(g) , relation between K_(p) and K_(c) is

In the equilibrium reaction, A(g) + 2B(g) + (g), the equilibrium constant, K_(c) is given by the expression

Define equilibrium constant. Write the equilibrium constant expression for the reaction of H_(2)(g)+I_(2)(g)hArr2HI(g) and its reverse reaction. How are the two equilibrium constants related?

The equilibrium constant for the reaction, H_(2)(g) + I_(2)(g) hArr 2HI(g) is 64 at a certain temperature. The equilibrium concentrations of H_(2) and HI are 2 mol//L and 16 mol//L respectively. What is the equilibrium concentration ( "in "mol//L ) of I_(2) ?

The K_(p) values for the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) at 460^(@)C is 49. If the initial pressure of H_(2) and I_(2) are 0.5 atm respectively, determine the partial pressure of each gases at equilibrium.

K_(c) for the reaction N_(2)(g)+3H_(2)(g)hArr2N_(3)(g) is 0.5 at 400K find K_(p)

At 700K equilibrium constant for the reaction : H_(2)(g) +I_(2)(g)hArr2HI(g) is 54.8 . If 0.5mol^(-1) of HI(g) is present at equilibrium at 700K . What are the concentration of H_(2)(g) and I_(2)(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700K ?