Given `N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g),K_(1)` `N_(2)(g)+O_(2)(g)hArr2NO(g),K_(2)` `H_(2)(g)+(1)/(2)O_(2)hArrH_(2)O(g),K_(3)` The equilibrium constant for `2NH_(3)(g)+(5)/(2)O_(2)(g)hArr2NO(g)+3H_(2)O(g)` will be
A
`K_(1)K_(2)K_(3)`
B
`(K_(1)K_(2))/(K_(3))`
C
`(K_(2)K_(3)^(3))/(K_(1))`
D
`(K_(1)K_(3)^(2))/(K_(3))`
Text Solution
Verified by Experts
The correct Answer is:
d
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
For the gaseous reactions (I) and (II) the equilibrium constants are X and Y respectively. I. (1)/(2)N_(2)(g) + O_(2) (g) hArr NO_(2)(g) (II) 2NO_(2)(g) hArr N_(2)O_(4) (g) Using the above reactions the equilibrium constant Z for the reaction (III) given below is III. N_(2)O_(4)(g) hArr N_(2)(g) + 2O_(2) (g)
The following equilibria are given N_2+3H_2 harr 2NH_3 , K_c=K_1 , N_2+O_2 harr 2NO, k_c=K_2 , H_2+1/2 O_2 harr H_2O, K_C = K_3 The equilibrium constant of the reaction. 2NH_3+5/2 O_2 harr 2NO+3H_2O in the terms of K_1,K_2 and K_3 is
In how many of the following entropy increases? {:((a) N_(2(g)) + 3H_(2(g)) rarr 2NH_(3(g)),(b)PCl_(5(g)) rarr PCl_(3(g)) + Cl_(2(g))),((c ) H_(2)O_((s)) rarr H_(2)O_((g)),(d)H_(2)O_((l)) rarr H_(2)O_((g))),((e ) 2NaHCO_(3(s)) rarr Na_(2)CO_(3(s)) + H_(2)O_((g)) + CO_(2(g)),(f ) NH_(2)CO_(2)NH_(4(s)) rarr 2NH_(3(g)) + CO_(2(g))),((g) H_(2)O_((l)) rarr H_(2)O_((s)),(h) CO_(2(s)) rarr CO_(2(g))):}
{:(Lis - I("Reaction"), List -II((K_(p))/(K_(c)))),((A)A_(2)(g) + 3B_(2)(g) hArr 2AB_(3)(g),(P)(RT)^(2)),((B) A_(2) (g)+ B_(2) (g) hArr 2 AB(g) ,(Q) (RT)^(@)),((C) A(s) + (3)/(2) B_(2) (g) hArr AB_(3)(g),(R) (RT)^(1//2)),((D) AB_(2) (g) hArr AB(g) +(1)/(2) B_(2)(g),(S) (RT)^(-1//2)):}
In which of the following reactions, the formation of product is favoured by decrease in temperature ? (1) N_(2)(g)+O_(2)(g)hArr2NO(g), DeltaH^(@)=181 (2) 2CO_(2)(g)hArr2CO(g)+O_(2)(g), DeltaH^(@)=566 (3) H_(2)(g)+I_(2)hArr2HI(g), DeltaH^(@)=-9.4 (4) H_(2)(g)+F_(2)(g)hArr2HF(g),DeltaH^(@)=-541
Derive the relation between K_(p) and K_(c) for the equilibrium reaction. N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)
For the equilibrium at 2.0 bar N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g)) [(del)/(del p) log K_(x)] = ?
Passage: When all the coefficients in a balanced chemical equation are multiplied by a constant factor X the equilibrium constant (originally K) becomes K^J . Similarly, when balanced equations are added together, the equilibrium constant for the combined process is equal to the product of the equilibrium constants for each step. Equilibrium constant of the reversed reaction is numerically equal to the reciprocal of the equilibrium constant of the original equation. Unit of K_p = ("atm")^(Deltan) , Unit of K_c =("mol" L^(-1))^(Deltan) Consider the two reactions: XeF_(6(g))+H_(2)O_((g)) harr XeOF_(4(g))+2HF_((g)), K_(1)" "XeO_(4(g))+XeF_(6(g)) harr XeOF_(4(g))+XeO_(3)F_(2(g)), K_(2) Then the equilibrium constant for the following reaction will be XeO_(4(g))+2HF_((g)) harr XeO_(3)F_(2(g))+H_(2)O_((g))
Unit of K_p for NH_4COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) is
Which of the following reactions will get affected by increasing the pressure? Also mention whether chasnge will cause the reaction to go into forward or backward direction. (i) COCl_(2)(g)hArrCO(g)+Cl_(2)(g) (ii) CH_(4)(g)+2S_(2)(g)hArrCS_(2)(g)+2H_(2)S(g) (iii) CO_(2)(g)+C(s)hArr2CO(g) (iv) 4NH_(3)+(g)+5O_(2)(g)hArr4NO(g)+6H_(2)O(g)