When sulphur ( in the form of `S_(8))` is heated at temperature `T`, at equilibrium , the pressure of `S_(8)` falls by `30%` from `1.0 atm`, because `S_(8)(g)` in partially converted into `S_(2)(g)`. Find the value of `K_(P)` for this reaction.
A
`2.96`
B
`6.14`
C
`204.8`
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
a
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
For the reaction C(s) + CO_(2) (g) hArr 2CO(g). the partial pressures of CO_(2) and CO are 2.0 and 4.0 atm respectively at equilibrium. What is the value of K_(p) for this reaction?
Find the value of "S" for (7,S),(3,-2) (7,8) are collinear.
The value of K_(p) for the reaction 2H_(2)S(g) hArr 2H_(2)(g) +S_(2)(g) is 1.2 xx 10^(-2) at 1065^(circ)C . The value of K, for this reaction is
A sample of HI(g) is placed in flask at a pressure of 0.2 atm. At equilibrium the partial pressure of HI(g) is 0.04 atm. What is K_(p) for the given equilibrium ? 2HI(g)hArrH_(2)(g)+I_(2)(g)
In the reaction, C_((s)) + CO_(2(g)) harr 2CO_((g)) the equilibrium pressure is 12 atm. If 50% of CO_(2) reacts, calculate K_(P) . If K_(P)= y^(2) then what is 'y" ?
In the reaction C_((s)) + CO_(2(g)) hArr CO_(2(g)) , the equilibrium pressure is 6.75 atm. If 50% of CO_(2) reacts then the find value of K_(p) .
Radius of sulphur atom is 102 pm. SSS angle is 105^(@) . What is the diameter of the sphere from the centre of S_(8) molecule?
For the following reaction NH_(4)HS_((s)) harr NH_(3(g))+H_(2)S_((g)) the total pressure at equilibrium is 30 atm. The value of K_(P) is