A1 273 K and I atm, I Lof `N_(2)O_(4(g))` decomposes to `NO_(2(g))` as given, `N_(2)O_(4(g)) 2NO_(2(g))`, At equilibrium . original volume is 25% lessthan the exisiting volume percentage decomposition of `N_(2)O_(4(g))` is thus,
A
`0.25`
B
`0.33`
C
`0.66`
D
`0.5`
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
N_(2(g))+O_(2(g))rarr 2NO_(2(g))-Q is ……………..
A sample of N_(2)O_(4(g)) with a pressure of I atm is placed in a flask. When equilibrium is reached, 20% N_(2)O_(4(g)) has been converted to NO_(2(g)) .N_(2)O_(4(g)) hArr 2NO_(2(g)) , If the orginal pressure is made 10% of the earlier, then percent dissociation will be
For the first order reaction 2N_(2)O_(5(g))to4NO_(2(g))+O_(2(g))
The volume occupied by O_2 gas at STP which is obtained by the decomposition of 17g of H_2O_2 is
What is the mole percentage of O_(2) in a mixture of 7g of N_(2) and 8g of O_(2) ?
What is the mole percentage of O_(2) in a mixture of 7g of N_(2) and 8g of O_(2) ?
N_(2(g)) + 2O_(2(g)) rarr 2NO_(2) + xkJ, 2NO_((g)) + O_(2(g)) rarr 2NO_(2(g)) + ykJ . The enthalpy of formation of NO is