`N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g))` for the reaction initially the mole ratio was 1: 3 of `N_(2). H_(2)`. At equilibrium 50% of each has reacted. If the equilibrium pressure is p, the partial pressure of `NH_(3)` at equilibrium is
A
`4.5 atm`
B
`3.0`atm
C
`2.0`atm`
D
`1.5atm`
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
In the reaction 2 SO_(3 (g)) , hArr 2 SO_(2 (g)) + O_(2 (g)) , SO_(3 (g)) is 50 % dissociated at 27^(@)C when the equilibrium pressure is 0.5 atm . Partial pressure of SO_(3 (g)) at Equilibrium is
N_(2(g)) + 3H_(2(g)) hArr 2NH_(3(g)) . If some HCl gas is passed into the reaction mixture at the equilibrium of this R reaction,
N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g)) is a gaseous phase equilibrium reaction taking place at 400K in a 5 L flask. For this
K_p for the reaction NH_4HS (s) leftrightarrow NH_3(g) +H_2S (g) at certain temperature is 9 bar^2 Calculate the equilibrium pressure.
Consider the following reaction equilibrium N_(2)(g)+ 3H_(2)(g) hArr 2NH_(3) Initially, 1 mole of N_(2) and 3 moles of H_(2) are taken in a 2 2L flask. At equilibrium state, if the number of moles of N_(2) is 0.6, what is the total number of moles of all gases present in the flask?
For N_(2) + 3 H_(2) hArr 2 NH_(3) , continous removal of NH_(3) maintains the following condition
Peqfor NH_(4)COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) at certain temperature is 0.9 atm. Then, partial pressure of Ammonia at equilibrium (in atm)