Ammonia under a pressure of 1.5 atm at `27^(@)`C is heated to `374^(@)`C in a closed vessel in the presence of a catalyst. Under the conditions, `NH_(3)` is partially decomposed according to the equation. `2NH_(3) hArr N_(2) + 3H_(2)` the vessel is such that the volume remains etfectively constant where as pressure increases to 50 atm. Calculate the percentage of `NH_(3)` actually decomposed
A
`65%`
B
`61.3%`
C
`62.5%`
D
`64%`
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
For the reaction 2NH_(3) hArr N_(2) + 3H_(2) equilibrium constant at 25^(@) C and 400^(@) C and 3.5 and 35 respcctively. This means that the forward reaction is:
Pure ammonia is placed in a vessel at a temperature where its degree of dissociation (alpha) is appreciable. At equilibrium 2NH_(3) = N_(2) + 3H_(2) .
For the reaction, N_(2(g)) + 3H_(2(g)) rarr 2NH_(3(g)) . Heat of reaction at constant volume exceeds the heat of reaction at constant pressure by the value of xRT. The value of x is______
In the equation N_(2)+3H_(2) hArr 2NH_(3) the equality realationship between (d[NH_(3)])/(dt) and -(d[H_(2)])/(dt) is
For the reaction, N_(2) + 3H_(2) hArr 2NH_(3) in a vessel, equal moles of N_(2) and H_(2) are mixed to attain equilibrium.
For the following reaction NH_(4)HS_((s)) harr NH_(3(g))+H_(2)S_((g)) the total pressure at equilibrium is 30 atm. The value of K_(P) is
In the reaction 2 SO_(3 (g)) , hArr 2 SO_(2 (g)) + O_(2 (g)) , SO_(3 (g)) is 50 % dissociated at 27^(@)C when the equilibrium pressure is 0.5 atm . Partial pressure of SO_(3 (g)) at Equilibrium is