At 1000 K , a sample of pure `NO_(2)` gases decomposes as : `2NO_(2)(g)hArr2NO(g)+O_(2)(g)` The equilibrium constant `K_(P)` is 156.25 atm .Analysis showns that the partial pressure of `O_(2)` is 0.25 atm at equilibrium .The parital pressure o f`NO_(2)` at equilibrium is :
A
`0.01`
B
`0.02`
C
`0.04`
D
none of these
Text Solution
Verified by Experts
The correct Answer is:
b
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
Kp value for 2SO_(2(g)) O_(2(g)) hArr 2SO_(3(g)) is 5.0 atm^(-1) . What is the cquilibrium partial pressure of O_(2) if the equilibrium pressures of SO_(2) and SO_(3) are equal ?
For the equilibrium , 2NOCl(g)hArr2NO(g)+Cl_(2)(g) the value of the equilibrium constant, K_(c) is 3.75xx10^(-6) at 1069K . Calculate the K_(p) for the reaction at this temperature ?
In the reaction C_((s)) + CO_(2(g)) hArr CO_(2(g)) , the equilibrium pressure is 6.75 atm. If 50% of CO_(2) reacts then the find value of K_(p) .
Steam is passed over hot carbon to attain the equilibrium at 400k. C_(s) + H_(2)O_((g)) hArr CO_((g)) + H(2(g)) . The equilibrium constant k = 1.34 (dimensionless) and the total pressure of the equilibrium mixture is 200 k.pa. Which one is correct when equilibrium is attained
K_(c) for the reaction N_(2)O(g)hArr2NO_(2)(g) is 4.63xx10^(-3) at 25^(2)C . a. What is the value of K_(p) at this temperature? b. At 25^(@)C , if the partial pressure of N_(2)O_(4)(g) at equilibrium is 0.2 atm, calculate equilibrium pressure of NO_(2)(g)
In the reaction 2 SO_(3 (g)) , hArr 2 SO_(2 (g)) + O_(2 (g)) , SO_(3 (g)) is 50 % dissociated at 27^(@)C when the equilibrium pressure is 0.5 atm . Partial pressure of SO_(3 (g)) at Equilibrium is
3O_(2) harr 2O_(3) . Oxygen is ozonised until the partial pressures of both gases become equal at equilibrium. Which statements are correct if P_(eq) = 10 atm ?