Home
Class 11
CHEMISTRY
For the reaction N(2)(g)+3H(2)(g)hArr...

For the reaction
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g),Delta H=-93.6KJmol^(-1)`
The number of moles of H at equilibrium will increase If :

A

volume is increased

B

volume is decreased

C

argon gas is added at constant volume

D

`NH_(3)` Is removed

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos

  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

K_(c) for the reaction N_(2)(g)+3H_(2)(g)hArr2N_(3)(g) is 0.5 at 400K find K_(p)

For the reaction, N_(2) + 3H_(2) hArr 2NH_(3) in a vessel, equal moles of N_(2) and H_(2) are mixed to attain equilibrium.

A mixture of 1.57 mol of N_(2) , 1.92 mol of H_(2) and 8.13 mol of NH_(3) is introduced into a 20L reaction vessel at 500K . At this temperature, the equilibrium constant, K_(c) for the reaction N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g) is 1.7xx10^(2) . Is the reaction mixture at equilibrium ? If not, what is the direction of the net reaction ?

in manufacture of NO, the reaction N_(2(g)) + O_(2(g)) hArr 2NO_((g)). Delta H + ve is favourable if :

A gaseous phase reaction taking place in 1 lit at 400K is given N_(2) (g) + 3H_(2) (g) hArr 2NH_(3) (g) starting with 1 mole N_(2) and 3 moles H_(2) equilibrium mixture required 250 ml of 1 M H_(2) SO_(4) . Thus , Ke is

Consider the following reaction equilibrium N_(2)(g)+ 3H_(2)(g) hArr 2NH_(3) Initially, 1 mole of N_(2) and 3 moles of H_(2) are taken in a 2 2L flask. At equilibrium state, if the number of moles of N_(2) is 0.6, what is the total number of moles of all gases present in the flask?