Home
Class 11
CHEMISTRY
The following equilibrium constants were...

The following equilibrium constants were determined at 1120k :
`2CO_((g)) hArr C_((s)) + CO_(2(g)) , Kp_(I) = 10^(-14) atm^(-1) , CO_((g)0 + Cl_(2(g)) hArr COCl_(2(g)) , Kp_(2) = 6 xx 10^(-3) atm^(-1)`
What is the equilibrium constant Kc for the following reaction at 1120K:
`C_((s)) + CO_(2(g)) + 2Cl_(2(g)) hArr 2CO_(2) Cl_((g))`

A

`3.31xx10^(11)M^(-1)`

B

`5.5xx10^(10)M^(-1)`

C

`5.51xx10^(6)M^(-1)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

The units of cquilibrium constant Kc for the following system H_(2(g)) + l_(2(g)) hArr 2HI_((g)) is

Passage: When all the coefficients in a balanced chemical equation are multiplied by a constant factor X the equilibrium constant (originally K) becomes K^J . Similarly, when balanced equations are added together, the equilibrium constant for the combined process is equal to the product of the equilibrium constants for each step. Equilibrium constant of the reversed reaction is numerically equal to the reciprocal of the equilibrium constant of the original equation. Unit of K_p = ("atm")^(Deltan) , Unit of K_c =("mol" L^(-1))^(Deltan) The equilibrium constants for the following reactions at 1400 K are given: 2H_2O_((g)) harr 2H_(2(g))+O_(2(g)) , K_1=2.1 xx 10^(-13) 2CO_(2(g)) harr 2CO_((g))+O_(2(g)) , K_2=1.4 xx 10^(-12) Then the equilibrium constant K for the reaction, H_(2(g))+CO_(2(g)) harr CO_((g)) + H_2O_((g)) is

For the reaction CO_((g)) + Cl_(2(g)) hArr COCl_(2(g)). The K_(p)//K_(c) is equal to

In what manner will increase of pressure affect the following equation ? C_((s)) + H_(2)O_((g)) hArr CO_((g)) + H_(2(g))

The equilibrium constant of the reaction, SO_(2)(g) + 1/2 O_(2)(g) hArr 2SO_(3)(g) is 5 xx 10^(-2)atm . The equilibrium constant of the reaction, 2SO_(3)(g) hArr 2SO_(2)(g) + O_(2)(g)

Following two eqilibrium is simultaneously establised in a container PCl_(s(g)) hArr PCl_((3)(g)) + Cl_((2)(g)), CO_((g)) + Cl_(2(g)) hArr COCl_((2)(g)) . If some Ni_((g)) is introduced in the container forming Ni(CO)_(4) then at new equilibrium

For the reaction CO_((g))+CI_(2(g)) harr COCI_(2(g)) . The K_p // K_c is equal to