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One mole of N(2) (g) is mixed with 2 mol...

One mole of `N_(2)` (g) is mixed with `2` moles of `H_(2)(g)` in a `4` litre vessel If `50%` of `N_(2)`(g) is converted to `NH_(3)`(g) by the following reaction :
`N_(2)(g)+3H_(2)(g)hArr2NH_(3)(g)`
What will the value of `K_(c)` for the following equilibrium ?
`NH_(3)(g)hArr(1)/(2)N_(2)(g)+(3)/(2)H_(2)(g)`

A

`256`

B

`16`

C

`(1)/(16)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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