Home
Class 11
CHEMISTRY
The equilibrium constant for the followi...

The equilibrium constant for the following reaction in aqueous solution is `0.90.`
`H_(3)BO_(3)+"glycerin"hArr(H_(3)BO_(3)-"glycerin")`
How many mole of glycerin should be added per litre of `0.10 M H_(3)BO_(3)` so that `80%` of the `H_(3)BO_(3)` is converted to the boric-acid glycerin complex ?

A

`4.44`

B

`4.52`

C

`3.6`

D

`0.08`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos
  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos
  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

H_(3)BO_(3) is

Basicity of H_(3)BO_(3) is

Boric acid (H_(3)BO_(3)) has

Boric acid (H_(3)BO_(3)) has

Basicity of H_3 BO_3 is

The correct order of increasing [H_(3) O^(+)] in the aqueous solution is

When orthoboric acid (H_(3)BO_(3)) is heated strongly the residue left is

Explain the following reaction between "PCl"_(3) and H_(3)PO_(3) .