For the reaction `AB_(2(g)) hArr AB_((g)) + B_((g))` if `alpha` is negligiable w.rt 1 then degree of dissociation `(alpha)` of `AB_(2)` is proportional to
A
`1/P`
B
`1/V`
C
`1/sqrtP`
D
`sqrtV`
Text Solution
Verified by Experts
Topper's Solved these Questions
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos
CHEMICAL EQUILIBRIUM
NARENDRA AWASTHI|Exercise Level 2|1 Videos
ATOMIC STUCTURE
NARENDRA AWASTHI|Exercise level 2|1 Videos
DILUTE SOLUTION
NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos
Similar Questions
Explore conceptually related problems
For the reaction CO_((g)) + Cl_(2(g)) hArr COCl_(2(g)). The K_(p)//K_(c) is equal to
For the reaction CO_((g))+CI_(2(g)) harr COCI_(2(g)) . The K_p // K_c is equal to
For the reaction PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) . Which of the graph "is"//"are" correct?
The gascous reaction A_((g)) + B_((g)) hArr 2C_((g)) + D_((g)) + q kJ is most favoured at :
For the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) the forward reaction at constant temperature is favoured by
For the equilibrium AB_((g)) harr A_((g)) +B_((g)) , at a given temperaturer (1)/(3) rd of AB is dissociated then (P)/(K_(P)) will be numerically equal to ____
For PCl_(5 (g)) hArr PCl_(3 (g)) + Cl_(2 (g)) at equilibrium , K_(P) = P//3 . Then degree of dissociation of PCl_(5) at that temperature is
The yield of product in the reaction 2A_((g)) + B_((g)) hArr 2C_((g)) + Q K J would be lower at :
PCl_(5) dissociates as follows in a closed reaction vessel PCI_(5(g)) harr PCl_(3(g)) + Cl_((g)) . If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is x, the partial pressure of PCI_(3) will be