Home
Class 11
CHEMISTRY
Heating a lI group metal cabonate leads ...

Heating a lI group metal cabonate leads to decomposition on `"BaCO"_(3(s)) hArr BaO_((s)) + CO_(2(g)) `, equilibrium will shift left

A

by addition of BaO (s)

B

by addition of `CO_(2)(g)`

C

by decreasing the temperature

D

by decreasing the volume of the vessel

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 1 (Q.93 To Q.122)|1 Videos

  • CHEMICAL EQUILIBRIUM

    NARENDRA AWASTHI|Exercise Level 2|1 Videos

  • ATOMIC STUCTURE

    NARENDRA AWASTHI|Exercise level 2|1 Videos

  • DILUTE SOLUTION

    NARENDRA AWASTHI|Exercise Level 3 - Match The Column|1 Videos

Similar Questions

Explore conceptually related problems

Comment on C_((s))+O_(2(g)) to CO_(2(g))+Heat equation.

Unit of K_p for NH_4COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) is

C_((s))+O_(2(g))rarr CO_(2(g))+Q is ………………….

Which of the following statements are not true about the following decomposition reaction? 2KCl_(3(s)) rarr 2KCl_((s)) +3O_(2(g))uarr

Steam is passed over hot carbon to attain the equilibrium at 400k. C_(s) + H_(2)O_((g)) hArr CO_((g)) + H(2(g)) . The equilibrium constant k = 1.34 (dimensionless) and the total pressure of the equilibrium mixture is 200 k.pa. Which one is correct when equilibrium is attained

For CaCO_(3)(S) hArr CaO(s) + CO_(2) (g), Delta H = + Q at equilibrium. to shift equilibrium towards right,

{:(Lis - I, List -II),((A) H_(2) (g) + I_(2)(g) hArr 2HI(g),(P)"Unaffected by inert gas addition "),((B)CaCO_(3) (s) hArr CaO(s) + CO_(2) (g),(Q)" Forward shift by rise in pressure and backward shift by inert gas addition at constant pressure "),((C) N_(2) (g) + 3H_(2) + (g) hArr 2NH_(3) (g) , (R)" Unaffected by increase in pressure"),((D) PCl_(3) (g) hArr PCl_(3) (g) + Cl_(2) (g) ,(S)"ackward shift by rise in pressure and forward shift by inert gas addition at constant pressure "):}

K_(p) = 1, For the equilibrium CaCO_(3(s)) hArr CaO_((s)) + CO_(2(g)) . The temperature of the reaction can be given as :

H_(2)S_((g)) intially at a pressure of 10 atm anda temperature of 800K, dissociates as 2H_(2)S_((g)) hArr 2H_(2) +S_(2(g)) At equilibrium, the partial pressure of S, vapour is 0.02 atm. Thus, K_(p) is

The equilibrium constant of the reaction, SO_(2)(g) + 1/2 O_(2)(g) hArr 2SO_(3)(g) is 5 xx 10^(-2)atm . The equilibrium constant of the reaction, 2SO_(3)(g) hArr 2SO_(2)(g) + O_(2)(g)