Solubility of Hg_2Cl_2 in a solvent is S moles/ litre.Its solubility product will be
If the solubility of Ca_(3)(PO_(4))_(2) in water is 'X' mol L_(-1) , its solubility product in mol^(5)L^(-5) is
The solubility of CaF_(2) is 2xx10^(-4) mole /litre . Its solubility product is
A solution which remains in equilibrium with undissolved solute is said to be saturated. The concentration of a saturated solution at a given temperature is called solubility. The product of concentration of ions in a saturated solution of an electrolyte at a given temperature, is called solubility product (K_(sp)) . For the electrolyte, A_(x),B_(y),:A_(x),B_(y(s)) rarr xA^(y+)+ y^(Bx-) , with solubility S, the solubility product (K_(sp)) =x^(x)xxy^(y) xx s^(x+y) . While calculating the solubility of a sparingly soluble salt in the presence of some strong electrolyte containing a common ion, the common ion concentration is practically equal to that of strong electrolyte. If in a solution, the ionic product of an clectrolyte exceeds its K_(sp) , value at a particular temperature, then precipitation occurs. The solubility of PbSO_(4) , in water is 0.303 g/l at 25^(@) C, its solubility product at that temperature is
At a certain temperature, the r.m.s. velocity for O_2 is 400 m/sec. At the same temperature. the r.m.s velocity for H_2 molecule will be
At certain temperature, the hydroxyl ion concentration of pure water is 8.4 xx 10^(-8) M . Calculate the ionic product at this temperature.
NARENDRA AWASTHI-IONIC EEQUILIBRIUM-Assertin-Reason Type Questions