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For a reversible adiabatic ideal gas exp...

For a reversible adiabatic ideal gas expansion `(dp)/(p)` is equal to

A

`gamma(dV)/(V)`

B

`-gamma(dV)/(V)`

C

`((gamma)/(gamma-1))(dV)/(V)`

D

`(dV)/(V)`

Text Solution

Verified by Experts

The correct Answer is:
B
`PV^(gamma)` = constant, `P.gammaV^(gamma-1).dV+V^(gamma).dP=0`
`therefore" "(dP)/(P)=-gamma.(dV)/(V)`
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