Home
Class 11
CHEMISTRY
Calculate average molar heat capacity at...

Calculate average molar heat capacity at constant volume of gaseous mixture contained 2 mole of each of two ideal gases `A(C_(v,m)=(3)/(2)R)` and `B(C_(v,m)=(5)/(2)R) :`

A

R

B

2R

C

3R

D

8R

Text Solution

Verified by Experts

The correct Answer is:
B

Average `C_(v,m)=(n_(1)C_(v,m_(1))+n_(2)C_(v,m_(2)))/(n_(1)+n_(2))`
`=(2xx(3)/(2)R+2xx(5)/(2)R)/(2+2)=2R`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|6 Videos
  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|2 Videos
  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|20 Videos

Similar Questions

Explore conceptually related problems

What is the most likely value for C_r (molar heat capacity at constant temperature)?

An ideal gas has molar heat capecity C_(v) at constant volume. The gas undergoes a process where in the temperature changes as T=T_(0)(1+alphaV^(2)) , T and V are temperature and volume respectively, T_(0) and alpha are positive constant.The molar heat capecity C of the gas is given as C=C_(v)+Rf(V), where, f (V) is a funtion of volume. The expression for f (V) is

A mixture of n_(1) moles of monoatomic gas and n_(2) moles of diatomic gas has (C_(p))/(C_(v))=gamma=1.5