For the reaction PCl_(5(g)) harr PCl_(3(g)) + Cl_(2(g)) . Which of the graph "is"//"are" correct?
Calculate the equilibrium constant (in multiples of 10^(-4) ) for the reaction PCl_(5(g)) rarr PCl_(3(g)) + Cl_(2(g)) at 400K, if Delta H^(0) = 77.2KJ "mole"^(-1) and Delta S^(0) = 122JK^(-1) "mole"^(-1)
For the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) the forward reaction at constant temperature is favoured by
Consider the following reaction, PCl_(5) (g) hArr PCl_(3) (g) + Cl_(2)(g) the forward reaction at constant temperature is favoured by
Initially 0.8 mole of PCl_(5) and 0.2 mole of PCl_(3) are mixed in one litre vessel . At equilibrium 0.4 mole of PCl_(3) is present . The value of K_(C) for the reaction PCl_(5(g)) hArr PCl_(3(g)) + Cl_(2(g)) is
At 27^(@)C, K_(p) value for the reversible reaction PCl_(5)(g)harrPCl_(3)(g)+Cl_(2)(g) is 0.65, calculate K_(c) .
For the following reaction PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g)0.4 mole of Cl_(2) are taken in a 1 litre flask. If K_(c)=0.2 predict the direction in which reaction proceeds.
The degree of dissociation is 0.4 at 400 K and a I atm for the gaseous reaction: PCI_(5(g)) hArr PCl_(3(g)) +Cl_(2(g)) : assuming ideal behaviour of gases, calculate the density of cquilibrium mixture at 400K and latm
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column