One mole of an ideal gas undergoes a change of state (2.0) atm, 3.0 L) to (2.0 atm, 7.0 L) with a change in internal energy `(DeltaU) = 30` L-atm. The change in enthalpy `(DeltaH)` of the process in L-atm :
A
22
B
38
C
25
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
At constant pressure, `DeltaH=DeltaU+P.DeltaV` `=30 + 2xx4` =38 atm-L
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