One mole of non`-` ideal gas undergoes a change of state `(1.0 atm, 3.0L, 200 K )` to `(4.0 atm, 5.0L,250 K)` with a change in internal energy `(DeltaU)=40 L-atm`. The change in enthalpy of the process in `L-atm`,
A
43
B
57
C
42
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
When both P and V are changing `" "DeltaH=DeltaU +Delta(PV)` `" "DeltaU+(P_(2)V_(2)-P_(1)V_(1))` `" "DeltaH=40+(20-3)` = 57 L-atm
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