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When two moles of an ideal gas (C(p.m.)=...

When two moles of an ideal gas `(C_(p.m.)=(5)/(2)R)` heated form 300K to 600K at constant pressure, the change in entropy of gas `(DeltaS)` is:

A

`(3)/(2) R ln 2`

B

`-(3)/(2) R ln 2`

C

`5R ln 2`

D

`(5)/(2) R ln 2`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaS=nC_(p,m)ln.(T_(2))/(T_(1))`
`=2xx(5)/(2)Rln.(600)/(300)`
`=5R " ln "2`
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