What is the change in entropy when `2.5` mole of water is heated from `27^(@)C` to `87^(@)C`? Assume that the heat capacity is constant `(C_(p))_(m)(H_(2)O)=4.2J//g=k,ln(1.2)=0.18)`
Find the change in internal energy in joule when 20gm of a gas is heated from 20^(@)C to 30^(@)C (G = 0.18 kcal/kg K, J = 4200J/kcal)
A 210 W heater is used to heat 100 g water. The time required to raise the temperature of this water from 25^(@)C to 100^(@)C is (specific heat capacity of water =4200" J/Kg-"^(@)C )
As per second law of thermodynamics a process taken place spontaneously if and only if the entropy of the universe increases due to the process. Change in entropy is given by Delta S = (Q_(rev))/(T) A gas C_(V) = (0.2 T) Cal K^(-1) . What is the change in its entropy when one mole of it is heated from 27^(@)C to 127^(@)C at constant volume ?
Find the change in internal energy in joule, when 10g of air is heated from 30^(@)C" to " 40^(@)C (C_(V)=0.172"kcal/kg K", J=4200" J/kcal")
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column