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In the isothermal expansion of an ideal ...

In the isothermal expansion of an ideal gas

A

`DeltaG = DeltaS`

B

`DeltaG = DeltaH`

C

`DeltaG = - T. DeltaS`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
For ideal gas isothermal expansion `DeltaH = 0`
`therefore" "DeltaG=-T.DeltaS`
where `" "DeltaS=nRln((V_(2))/(V_(1)))`
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