The entropies of `H_(2)` (g) and H (g) are 130.6 and 114.6 J `mol^(-1)K^(-1)` respectively at 298 K. Using the data given below calculate the bond energy of `H_(2)` (in kJ/mol) : `H_(2)(g)rarr2H(g),DeltaG^(@)=406.6kJ`
The molar entropies of HI_((g)), H_((g)) and I_((g)) at 298K are 206.5, 114.6, and 180.7 J mol^(-1)K^(-1) respectively. Using the DeltaG^(@) given below, calculate the bond energy of HI. HI_((g)) rarr H_((g)) + I_((g)), DeltaG^(@) = 271.8kJ (Give your answer after divide with 49.7)
The absolute entropies of H_(2(g)), O_(2(g)) and H_2O_((l)) are respectively 130.6, 205.1 and 69.9 JK-mol^(-1) . Calculate the value of DeltaS for the formation of one mole liquid water.
Given Delta H_r ^@ for CO_2(g) , CO_(g) and H_2O(g) are -393.5, -110.5 and -241.8 KJ mol^-1 respectively. The Delta H_r^@ (in KJ mol^-1] for the reaction CO_2(g) + H_2(g) rightarrow CO_(g) + H_2O(g) is
If the bond energies of H-H, Br-Br and HBr are 433, 192 and 364 kJ mol^(-1) respectively, then DeltaH^@ for the reaction : H_(2(g)) + Br_(2(g)) rarr 2HBr_((g)) is
At T(K), the ratio of kinetic energies of 4g of H_(2) (g) and 8g of O_(2) (g) is
Heat of formation of 2 moles of NH_(3)(g) " is" -90 kJ l bond energies of H-H and N-H bonds are 435 kJ and 390 kJ mol^(-1) respectively. The value of the bond energy of N -= N is (1000- (x^(2) + x +25)) kJ/mol What is x ?
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column