Home
Class 11
CHEMISTRY
Given : C("diamond")+O(2)rarrCO(2),De...

Given :
`C("diamond")+O_(2)rarrCO_(2),DeltaH=-395 kJ`
`C("graphite")+O_(2)rarrCO_(2),DeltaH=-393 kJ`
The enthalpy of formation of diamond from graphite is

A

`+ 2.0 kJ`

B

`-1.5 kJ`

C

`-788 kJ`

D

788 kJ

Text Solution

Verified by Experts

The correct Answer is:
A
C (graphite) `rarr` C (diamond)
`DeltaH=395-393=2`
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.1 To Q.30)|6 Videos

  • THERMODYNAMICS

    NARENDRA AWASTHI|Exercise Level 1 (Q.31 To Q.60)|2 Videos

  • STOICHIOMETRY

    NARENDRA AWASTHI|Exercise Level 3 - Subjective Problems|20 Videos

Similar Questions

Explore conceptually related problems

Given that C + O_2 rarr CO_(2) , DeltaH^@ = -xkJ 2CO + O_2 rarr 2CO_2 , DeltaH^@ = -y kJ The enthalpy of formation of carbon monoxide will be

C_("graphite") + O_(2(g)) : Delta H = -393.5 kJ . Delta H of the above reaction cannot be

If S + O_(2) rarr SO_(2), DeltaH= -398.2kJ SO_(2) + (1)/(2) O_(2) rarr SO_(3), DeltaH= -98.7kJ , SO_(3) + H_(2)O rarr H_(2)SO_(4), DeltaH= -130.2 kJ H_(2) + (1)/(2) O_(2) rarr H_(2)O, DeltaH= -227.3kJ The enthalpy of formation of sulphuric acid at 298K will be

From the following data CH_(3)OH(l)+(3)/(2)O_(2)(g) rarr CO_(2)(g) +2H_(2)O(l) Delta_(r) H^(@)=-726 kJ mol^(-1) H_(2)(g)+(1)/(2)O_(2)(g) rarr H_(2)O(l), Delta _(r) H^(@)=-286 kJ mol^(-1) C("graphite") +O_(2)(g) rarr CO_(2)(g), Delta _(r) H^(@)=-393 kJ mol^(-1) The standard enthalpy of formation of CH_(3)OH(l)" in "kJ mol^(-1) is

If S + O_(2) rarr SO_(2), Delta H = -398.5 kJ SO_(2) + (1)/(2)O_(2) rarr SO_(3), Delta H= -98.7kJ , SO_(3) + H_(2)O rarr H_(2)SO_(4), Delta H= - 130.5kJ H_(2) + (1)/(2) O_(2) rarr H_(2)O, Delta H= -227.3kJ If magnitude of enthalpy of formation of sulphuric acid at 298K is 95x, x= ?