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The fat, C(57)H(104)O(6)(s), is metaboli...

The fat, `C_(57)H_(104)O_(6)(s)`, is metabolized via the following reaction. Given the enthalpies of formation, calculate the energy (kJ) liberated when 1.0 g of this fat reacts.
`C_(57)H_(104)O_(6)(s)+80 O_(2)(g)rarr57CO_(2)(g)=-52 H_(2)O(l)`
`Delta_(f)H^(@)(C_(57)H_(104)O_(6),s)=-70870" kJ"//"mol, "Delta_(f)H^(@)(H_(2)O,l)=-285.8 " kJ"//"mol"`,
`Delta_(f)H^(@)(CO_(2),g)=-393.5 " kJ"//"mol"`

A

37.98

B

40.4

C

33.4

D

30.2

Text Solution

Verified by Experts

The correct Answer is:
A
`Delta_(r )H^(@)=57 xx (-393.5)+52xx(-285.8)-(-70870)`
`=-33578.9" kJ"//"mol"`
`=-(33578.9)/(884)=-37.98 " kJ"//"mol"`
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