Consider the following reaction: `H_(2)O(l)toH_(2)O(g)" "DeltaH_(1)=44kJ` `2CH_(3)OH(l)+3O_(2)to4H_(2)O(l)+2CO_(2)(g)" "DeltaH_(2)=-1453kJ` What is the value of `DeltaH` for second reaction if water vapour instead of liquid water is formed as product?
The enthalpy of the reaction H_(2(g)) + O_(2(g)) rarr H_2O_((g)) is DeltaH_1 and that of H_(2(g)) + O_(2(g)) rarr H_(2)O_((l)) is Delta H_2 . Then
For the reaction 2H_(2)O_((l)) rarr H_(3)O_((aq))^(+) + OH_((aq))^(-) , the value of Delta H is
The enthalpy of the reaction H _(2 (g)) + 1/2 O _(2(g)) to H _(2) O _((g)) is Delta H _(1) and that of H _(2(g)) + 1/2 O _(2(g)) to H _(2) O _((l)) is Delta H _(2). Then
Balance the following equation by electron transfer method. NH_(3)(g) + O_(2)(g) rarr NO (g) + H_(2)O(l)
For the reaction 2H_(2(g)) + o_(2(g)) rarr 2H_(2)O_((g)), Delta H^(@) = - 573.2 kJ . The heat of decomposition of water per mol is:
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column