The enthalpy of neutraliztion of weak base A OH and a strong base BOH by HCl are -12250 cal/mol and -13000 cal/mol respectively . When one mole of HCl is added to a solution containting 1 mole of A OH and 1 mole of BOH , the enthalpy change was -12500 cal/mol . In what ratio is the acid distribution between A OH and BOH?
A
`2 : 1`
B
`2 : 3`
C
`1 : 2`
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
A
`-12250x-13000(1-x)=-12500` `750 x = 500 implies x=2//3" and "y = 1//3` So, `" "(x)/(y)=(2)/(1)`
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