Boron can undergo the following reactions with the given enthalpy changes : `2B(s)+(3)/(2)O_(2)(g)rarrB_(2)O_(3)(s)," "DeltaH=-1260 " kJ"` `2B(s)+3H_(2)(g)rarrB_(2)H_(6)(g)," "DeltaH=30 " kJ"` Assume no other reactions are occuring. If in a container (operating at constant pressure) which is isolated from the surrounding, mixture of `H_(2)` (gas) and `O_(2)` (gas) are passed over excess of B(s), then calculate the molar ratio `(O_(2) : H_(2))` so that temperature of the container do not change :
A
`15 : 2`
B
`42 : 1`
C
`1 : 42`
D
`1 : 84`
Text Solution
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The correct Answer is:
D
No. of moles of `O_(2)` required to supplied 30 kJ heat to second reaction `=(30)/(1260)xx(3)/(2)=(1)/(28)` `Son_(O_(2)):n_(H_(2))=(1)/(28):3 " or "1 : 84`
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