Two mole of an ideal gas is heated at constant pressure of one atmosphere from `27^(@)C` to `127^(@)C`. If `C_(v, m) = 20 + 10^(-2) TJK^(-1) mol^(-1)`, then q and `Delta U` for the process are respectively.
10 mole of an ideal gas is heated at constant pressure of one atmosphere from 27^(@)C to 127^(@)C . If C_(v, m) = 21.686 + 10^(-3) T , then Delta H for the process is x xx 10^(5) J1 . Then x is
One mole of an ideal gas for which C_(V)= 3//2R heated at a constant pressure of 1 atm from 25^(0)C "to" 100^(0)C What will be the amount of work done in the process?
One mole of an ideal gas for which C_(V)= 3//2R heated at a constant pressure of 1 atm from 25^(0)C "to" 100^(0)C What will be the amount of heat change at constant pressure?
At 27^@C , one mole of an ideal gas exerted a pressure of 0.821 atmospheres. What is its volume in litres ? (R = 0.082 "lit-atm/mol"^(-1) K^(-1))
0.5 mole of diatomic gas at 27^(@)C is heated at constant pressure so that its volume is tripled. If R = 8.3 J "mole"^(-1)k^(-1) then work done is
An ideal gas is heated from 20^(@)C to 40^(@)C under constant pressure. The change in internal energy is
A sample of an ideal gas has a volume of 0.5 litres at 27^@C and 750mm pressure. The number of moles of gas are
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column