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10 mole of an ideal gas is heated at con...

10 mole of an ideal gas is heated at constant pressure of one atmosphere from `27^(@)C` to `127^(@)C`. If `C_(v, m) = 21.686 + 10^(-3) T`, then `Delta H` for the process is `x xx 10^(5) J1`. Then x is

A

3000 J

B

3350 J

C

3700 J

D

`3181.4J, 2350J`

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(p,m)=(21.686+8.314+10^(-3)T)`
`=30+10^(-3)T`
`intDeltaH=intnC_(p,m)DeltaT`
`=10xxint(30+10^(-3)T).dT`
`DeltaH=10xx30(T_(2)-T_(1))+(10^(-3))/(2)xx[T_(2)^(2)-T_(1)^(2)]xx10`
= 30350 J
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