For a perfectly cyrstalline solid `C_(p,m)= a T^(3) + bT`, where a and b are constants. If `C_(p,m)` is 0.40 J/K mol at 10K and 0.92 J/K mol at 20K, then molar entropy at 20K is `0.2x xx R` joules. Then the value of x is
A
`0.92` J/K mol
B
`8.66` J/K mol
C
`0.813` J/K mol
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
C
`0.40=aT_(1)^(3)+bT_(1)` `0.40xxa(1000)+bxx10` `0.4=1000a+10b` …(1) `0.92=aT_(2)^(3)+bT_(2)` `rArr" "0.92=axx8000+20b` …(2) from Eqs. (1) and (2) `a = 2xx10^(-5)," "b=0.038` `S_(m)=int(aT^(3)+bT)/(T).dT` `=(a[T_(2)^(3)-T_(1)^(3)])/(3)+b[T_(2)-T_(1)]` `0.813"J/K-mol"`
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