Using listed informations, calculate `Delta_(r)G^(@)` (in kJ/mol) at `27^(@)C` `Co_(3)O_(4)(s)+4CO(g)rarr3Co(s)+4CO_(2)(g)` Given : At 300 K `DeltaH_(f)^(@)(kJ//mol)-891,-110.5,0.0,-393.5` `S^(@)(J//K.mol)102.5, 197.7, 30.0, 213.7`
Unit of K_p for NH_4COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) is
Consider the following reaction : CO_((g)) + 2H_(2(g)) hArr CH_(3)OH_((g)) Given : Delta_(r) H^(@) (CH_(3)OOH, g) = -201 kJ/mol, Delta_(r) H^(@) (CO, g) = -114 kJ/mol S^(@) (CH_(3)OOH, g) = 240 J/K-mol , S^(@) (H_(2), g) = 29 JK^(-1)mol^(-1) S^(@) (CO, g) = 198 J/mol-K , C^(@)_(p,m) (H_(2)) = 28.8 J/mol-K C^(@)_(p,m) (CO) = 29.4 J/mol-K , C^(@)_(p,m) (CH_(3)OH) = 44 J/mol-K and ln ((320)/(300)) = 0.06 , all data at 300 K Delta_(r) S^(@) at 300 K for the reaction is :
Consider the following reaction : CO_((g)) + 2H_(2(g)) hArr CH_(3)OH_((g)) Given : Delta_(r) H^(@) (CH_(3)OOH, g) = -201 kJ/mol, Delta_(r) H^(@) (CO, g) = -114 kJ/mol S^(@) (CH_(3)OOH, g) = 240 J/K-mol , S^(@) (H_(2), g) = 29 JK^(-1)mol^(-1) S^(@) (CO, g) = 198 J/mol-K , C^(@)_(p,m) (H_(2)) = 28.8 J/mol-K C^(@)_(p,m) (CO) = 29.4 J/mol-K , C^(@)_(p,m) (CH_(3)OH) = 44 J/mol-K and ln ((320)/(300)) = 0.06 , all data at 300 K Delta_(r) H^(@) at 300 K for the reaction is :
Consider the following reaction : CO_((g)) + 2H_(2(g)) hArr CH_(3)OH_((g)) Given : Delta_(r) H^(@) (CH_(3)OH, g) = -201 kJ/mol, Delta_(r) H^(@) (CO, g) = -114 kJ/mol S^(@) (CH_(3)OOH, g) = 240 J/K-mol , S^(@) (H_(2), g) = 29 JK^(-1)mol^(-1) S^(@) (CO, g) = 198 J/mol-K , C^(@)_(p,m) (H_(2)) = 28.8 J/mol-K C^(@)_(p,m) (CO) = 29.4 J/mol-K , C^(@)_(p,m) (CH_(3)OH) = 44 J/mol-K and ln ((320)/(300)) = 0.06 , all data at 300 K Delta_(r) S^(@) at 320 K is :
Calculate the equilibrium constant (in multiples of 10^(-4) ) for the reaction PCl_(5(g)) rarr PCl_(3(g)) + Cl_(2(g)) at 400K, if Delta H^(0) = 77.2KJ "mole"^(-1) and Delta S^(0) = 122JK^(-1) "mole"^(-1)
Give that C_(s) +O_(2_(g))to CO_(2_((g))), Delta H^(0)=-xkJ 2CO_((g))+O_(2_((g)))to 2CO_(2_((g))), Delta H^(0)=-ykJ .
Based on the values of B.E. given, Delta_(f)H^(0) " of " N_(2)H_(4(g)) is : Given BE of : N- N is 159 kJ mol^(-1) , H-H is 436 kJ mol^(-1), N =- N is 941 kJ mol^(-1), N-H is 398 kJ mol^(-1)
C _((s)) + O _(2 (g)) to CO _(2(g)) ,Delta H =-393.5kJ. This equation can not represent
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column