Determine `Delta U^(@) ` at 300K for the following reaction using the listed enthalpies of reaction : `4CO(g)+8H_(2)(g)to3CH_(4)(g)+CO_(2)(g)+2H_(2)O(l)` `C("graphite")+(1)/(2)O_(2)(g)to CO(g), DeltaH_(1)^(@)=-110.5KJ` ` CO(g)(1)/(2)O_(2)(g)toCO_(2)(g), DeltaH_(2)^(@)=-282.9KJ` `H_(2)(g)+(1)/(2)O_(2)(g)to H_(2)O(l), DeltaH_(3)^(@)=-285.8KJ` `C("graphite")+2H_(2)(g)to CH_(4)(g), DeltaH_(4)^(@)=-74.8KJ`
A
`-653.5` kJ
B
`-686.2` kJ
C
`-767.35` kJ
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
D
`DeltaH^(@)=-3DeltaH_(1)^(@)+DeltaH_(2)^(@)+2DeltaH_(3)^(@)+3DeltaH_(4)^(@)` `=-747.4kJ` `DeltaH^(@)=DeltaU^(@)+Deltan_(g)RT," where " Deltan_(g)=-8` `-747.4=DeltaU^(@)=(8xx8.314xx300)/(1000)` `DeltaU^(@)=-727.44kJ`
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