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What is the enthalpy of neutralization o...

What is the enthalpy of neutralization of HF against a strong base?
Given : `H^(+)(aq)+OH^(-)(aq)rarrH_(2)O(l),Delta_(r)H^(@)=-56kJ//mol`
`Delta_(s)H^(@)(HF,aq)=-329kJ//mol,Delta_(s)H^(@)(H_(2)O,l)=-285kJ//mol`
`Delta_(s)H^(@)(F^(-),aq)=-320 " kJ"//"mol"`

A

`-17` kJ/mol

B

`-38` kJ/mol

C

`-47` kJ/mol

D

`-43` kJ/mol

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta_(r)H^(@)=Delta_(r)H^(@)(H_(2)O,l)-Delta_(r)H^(@)(OH^(-),aq)=-229`
`-56 =- 285 -Delta_(r)H^(@)(OH^(-),aq),`
`Delta_(r)H^(@)(OH^(-),aq)=-229`
`HF(aq)+OH^(-)(aq)rarrF^(-)(aq)+H_(2)O(l)`
`Delta.H_("neut")^(@)=(-320-285)-(-329-229)`
=-47 kJ/mol
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