For the reaction taking place at certain temperature `NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g)` if equilibrium pressure is 3 X bar then `Delta_(r)G^(@)` would be
Unit of K_p for NH_4COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) is
Peqfor NH_(4)COONH_(2(s)) harr 2NH_(3(g))+ CO_(2(g)) at certain temperature is 0.9 atm. Then, partial pressure of Ammonia at equilibrium (in atm)
K_p for the reaction NH_4HS (s) leftrightarrow NH_3(g) +H_2S (g) at certain temperature is 9 bar^2 Calculate the equilibrium pressure.
For the following reaction NH_(4)HS_((s)) harr NH_(3(g))+H_(2)S_((g)) the total pressure at equilibrium is 30 atm. The value of K_(P) is
Derive the relation between K_(p) and K_(c) for the equilibrium reaction. N_(2)(g)+3H_(2)(g)hArr 2NH_(3)(g)
In the reaction C_((s)) + CO_(2(g)) hArr CO_(2(g)) , the equilibrium pressure is 6.75 atm. If 50% of CO_(2) reacts then the find value of K_(p) .
For the reaction in equilibrium: 2NOBr_((g)) hArr 2NO_((g)) + Br_(2(g)) If P_(Br_(2)) is (P)/(9) t equilibrium and P is total pressure, If (P)/(Kp) = x^(2) then what is x value.
In the equilibrium NH_(4) HS_(s) hArr NH_(3(g)) + H_(2) S_((g)) . the forward reaction can be favoured by
NARENDRA AWASTHI-THERMODYNAMICS-Level 3 - Match The Column