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Enthalpy of neutralization is defined as...

Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is `H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol`
If enthalpy of neutralization of `CH_(3)COOH` by NaoH is -49.86 kJ/mol then enthalpy of ionisation of `CH_(3)COOH` is

A

5.98 kJ/mol

B

`-5.98` kJ/mol

C

105.7 kJ/mol

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`-49.86=(Delta_("Iron")H)_(CH_(3)COOH)-55.84`
`(Delta_("Iron")H)_(CH_(3)COOH)=5.98 " kJ mol"^(-1)`
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