Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is `H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol` What is `Delta H^(0)` for complete neutralisation of strong diacidic base `A(OH)_(2) " by " HNO_(3)`?
A
`-55.84` kJ/mol
B
`111.68` kJ/mol
C
55.84 kJ/mol
D
None of these
Text Solution
Verified by Experts
The correct Answer is:
B
`Delta_(r )H=2xx(-55.84)=-111.68 " kJ"`
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Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol If enthalpy of neutralization of CH_(3)COOH by NaoH is -49.86 kJ/mol then enthalpy of ionisation of CH_(3)COOH is
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