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Enthalpy of neutralization is defined as...

Enthalpy of neutralization is defined as the enthalpy change when 1 mole of acid/base is completely neutralized by base/acid in dilute solution. For strong acid and strong base neutralization net chemical change is `H_((aq))^(+) + OH_((aq))^(-) rarr H_(2)O_((l)), Delta H_(r )^(0) -= - 55.84 kJ//mol`
Under the same conditions how many mL of 0.1M NaOH and 0.05 M `H_(2)A` (strong diprotic acid) should be mixed for a total volume of 100mL to produce the highest rise in temperature:

A

`25 : 75`

B

`50 : 50`

C

`75 : 25`

D

`66.66 : 33.33`

Text Solution

Verified by Experts

The correct Answer is:
B

`2NaOH+H_(2)ArarrNa_(2)A+2H_(2)O`
`(0.1V_(1))/(1000)" "(0.05V_(2))/(1000)`
`V_(1)+V_(2)=100" "....(1)`
`2xx(0.05 V_(2))/(1000)=(0.1V_(1))/(1000)`
`implies V_(1)=V_(2)`
`" "V_(1)=V_(2)=50mL`
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