Gibbs Helmholtz equation relates the enthalpy, entropy and free energy change of the process at constant pressure and temperature as `DeltaG=DeltaH-TDeltaS " (at constant P, T)"` In General the magnitude of `DeltaH` does not change much with the change in temperature but the terms `TDeltaS` changes appreciably. Hence in some process spontaneity is very much dependent on temperature and such processes are generally known as entropy driven process. When `CaCO_(3)` is heated to a high temperature it decomposes into CaO and `CO_(2)`, however it is quite stable at room temperature. It can be explained by the fact that
A
`Delta_(r )H` dominates the term `TDeltaS` at high temperature
B
the term `TDeltaS` dominates the `Delta_(r )H` at high temperature
C
at high temperature both `Delta_(r )S` and `Delta_(r )H` becomes negative
D
thermodynamics can not say anything about spontaneity
Text Solution
Verified by Experts
The correct Answer is:
B
`CaCO_(3)rarrCaO+CO_(2)" "DeltaH+ve` Reaction becomes spontaneous at high temperature because `TDeltaS` dominates over `DeltaH_(rxn)`.
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