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The rate at which a particular decay pro...

The rate at which a particular decay process occurs in a radio active sample, is proportional to the number of radio active nuclei present. If N is the number of radio active nuclei present at some instant, the rate of change of N is `(dN)/(dt) = - lambdaN`.

Consider radioavtive decay of A to B which may further decay, either to X or to Y, `lambda_(1),lambda_(2)` and `lambda_(3)` are decay constants for A to B decay, B to X decay and B of Y decay respectively. If at `t = 0` number of nuclei of A, B, `X` and Y are `N_(0), N_(0)`, zero and zero respectively and `N_(1),N_(2),N_(3),N_(4)` are number of nuclei `A,B,X` and `Y` at any intant.
At `t = oo`, which of the following is incorrect ?

A

cancer

B

eye cataract

C

DNA breakage

D

All of these

Text Solution

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The correct Answer is:
A
The radioactive waste present in the water increases the risk of damage to tissues, cells, DNA and other vital molecules. It potentially can cause programmed all death, genetic mutations, cancers, leukernia, birth defects and reproductive, immune and endocrine system disorders.
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Radio Activity

Radio Activity

Show that the decay rate R of a sample of radionuclide is related to the number of radioactive nuclei N at the same instant by the expression R=lambdaN .