Home
Class 11
CHEMISTRY
Calculate the weight of 0.1 mole of sodi...

Calculate the weight of 0.1 mole of sodium carbonate.

Text Solution

Verified by Experts

No. of moles of sodium carbonate = `("Wt.of "Na_2CP_3)/("M. Wt of "Na_2CO_3)`
Wt. of `Na_2CO_3` = No. of moles of `Na_2CO_3 xx M.W." of "Na.CO_3`
`=0.1xx106 = 10.6`g
Promotional Banner

Topper's Solved these Questions

  • MODEL PAPER 12

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - B|9 Videos
  • MODEL PAPER 12

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C|3 Videos
  • MODEL PAPER 11

    VGS PUBLICATION-BRILLIANT|Exercise SECTION - C|4 Videos
  • MODEL PAPER 2

    VGS PUBLICATION-BRILLIANT|Exercise SECTION C|5 Videos

Similar Questions

Explore conceptually related problems

Calculate the weight aof anhydrous sodium carbonate present in 200 mL of 0.2 M solution.

Calculate the weight of anhydrous sodium carbonate required to prepare 250ml of decimolar solution.

Calculate the weight of calcium calcium carbonate required to produce carbondioxide that is sufficient for conversion of one decimole sodium carbonate to sodium bicarbonate.

Mention some uses of sodium carbonate.

10 grams of CaCO_(3) is completely decomposed to x and CaO. 'x' is passed into an aqueous solution containing 0.1mole of sodium carbonate. What is the number of moles of sodium bicarbonate formed? (mol. wts: CaCO_(3) = 100, NaCO_(3) = 106, NaHCO_(3) = 84 )

Calculate the weight of sodium chloride present in 250mL of 0.1N solution.

Calculate the weight of sodium hydroxide present in 200ml of 0.5 M solution.

Calculate the weight of sodium oxalate present in 250 mL of seminormal solution.