There are eight persons A, B, C, D, E, F, G and H who were born on the same day of the same month of different year tile. 1950, 1954, 1962, 1971, 1978, 1982, 1995 and 1999 but not necessarily in the same order.
Note: Calculation done with respect to present year 2017 assuming month and date to be same as that of year of birth as next above. Each person is assumed to be born on same date & month of respected years.
F was born after 1978 but not born in 1995. Sum of present age of F and A is 81yr. Difference of present ages of A and H is less than nine. E is the oldest person. B was born in odd number year after H, but not born in 1995. Sum of present age of D and G is 61yr. D is younger than G.
How many persons were born before C?

Options

A. Four
B. Two
C. Seven
D. Five

Answer

D

Explanation

Step 1. From the given conditions, E is the oldest person. F was born after 1978 but not born in 1995. Sum of present age of F and A is 81yr. So, there will be two possible cases case 1 and case 2 in which F is either born, in 1982(then A is born in the year 1971) or in 1999(then A is born in the year 1954).

Step 2. As it is given that, Difference of present ages of A and His less than nine. B was born in odd number year after H, but not born in 1995.

Step 3. Using the rest of the conditions, Sum of present age of D and G is 61yr. D is younger than G. So, from (these statement cases I will be eliminated. Now continuing with case II, G was born in the year 1978 and D in the year 1995 and C was born in the year 1982. Hence, we get our final solution.