Six Bowlers are playing match in different days of a week i.e. Monday, Tuesday, Wednesday, Thursday, Friday and Saturday. Week starts from Monday. They all are taking different no. of wickets in the match. One Bowler can take at most 10 wickets. Three bowlers play match between E and M and both of them take odd numbered - wickets. Bowler who takes 5 wickets plays match just before O and just after D. Bowler who takes 6 wickets plays match in Wednesday. Two Bowlers play match, between F and N but both doesn't take even numbered wickets. Addition of wickets taken by M and O is 15. There are as many bowlers play the match before F as after the bowler who takes 9 wickets. F takes more than 2 wickets.
Who among the following person plays match on Friday?

Options

A. D
B. E
C. O
D. N

Answer

C

Explanation

From the given statements, bowler who takes 6 wickets plays match in Wednesday. Three bowlers play match between E and M and both of them take odd numbered wickets. Two Bowlers play match between F and N but both doesn.t take even numbered wickets. Bowler who takes 5 wickets plays match just before and just after D. There are as many bowlers play the match before F as after the bowler who takes 9 wickets. Here, we get two possibilities i.e. Case 1 and Case 2.

From the given statements ,addition of wickets taken by M and O is 15. One Bowler can take at most 10 wickets . So, they will take either 5 and 10 or 6 and 9 or 7 and 8 wickets . D takes 6 and N takes 5 wickets and M takes odd . numbered wicket . So , M and O will take 7 and 8 wickets respectively . Here , Case 1 is ruled out . F gets more than 2 wickets. F takes odd numbered wickets .
So , the final arrangement will be : -