A bob of a simple pendulum of mass 40gm with a positive charge `4xx10^(-6)C` is oscillating with time period. `'T_1'`. An electric field of intensity `3.6xx10^4 N//C` is applied vertically upwards now time period is `T_2`. The value of `('T_2')/(T_1)` is (`g=10m//s^2`)

Options

A. `0.16`
B. `0.64`
C. `1.25`
D. `0.8`

Answer

C