A galvanometer having a resistance of `50 Omega`, gives a full scale deflection for a current of 0.05 A. The length in meter of a resistance wire of area of cross section`2.97 xx 10^(-2) cm^2` that can be used to convert the galvanometer into an ammeter which can read a maximum of 5A current is (specific resistance of the wire = `5 xx 10^(-7) Omega - m`)

Options

A. 9
B. 6
C. 3
D. 1.5

Answer

C