An energy of 84000 J is required to raise the temperature of 2 kg of water from `60^@ C " to " 70^@ C`. Calculate the specific heat capacity of water.

Explanation

Specific heat capacity, `C = Q // m xx DeltaT`
Here, Q = 84000 J
m = 2kg
`DeltaT = 70^@ C – 60^@ C = 10^@C = 10 K`
`C = 84000 // 2 xx 10 = 4200 "J Kg"^(-1) K^(-1)`
The Specific heat capacity of water is `4200 "J Kg"^(-1) K^(-1)` .