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If abs(AxxB) =sqrt3 (vecA. vecB), then t...

If `abs(AxxB) =sqrt3 (vecA. vecB)`, then the value of `abs(A+ B)` is:

A

`sqrt(A^2 + B^2 + AB)

B

`sqrt(A^2 + B^2 + 3 AB)

C

`sqrt(A^2 + B^2 - AB)

D

A+B

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