The reaction of 4-bromobenzyl chloride with NaCN in ethanol leads to :

Options

A. 4-Bromobenzyl cyanide
B. 4-Cyanobenzyl chloride
C. 4-Cyanobenzyl cyanide
D. 4-Bromo-2-cyanobenzyl chloride

Explanation

To solve the problem of the reaction of 4-bromobenzyl chloride with NaCN in ethanol, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- 4-bromobenzyl chloride (C6H4BrCH2Cl)
- Sodium cyanide (NaCN)
- Ethanol (C2H5OH) as the solvent

### Step 2: Understand the Reaction Mechanism
The reaction proceeds via an SN2 mechanism. In an SN2 reaction, a nucleophile attacks the electrophile, resulting in the substitution of one group for another. Here, the nucleophile is CN⁻ from NaCN, and it will attack the carbon atom bonded to the chlorine in 4-bromobenzyl chloride.

### Step 3: Draw the Structure of 4-bromobenzyl Chloride
The structure of 4-bromobenzyl chloride can be represented as follows:

```
Br
|
C6H4-CH2-Cl
```

### Step 4: Identify the Site of Nucleophilic Attack
In the structure, the chlorine atom (Cl) is the leaving group. The nucleophile (CN⁻) will attack the carbon atom (CH2) that is bonded to the chlorine atom.

### Step 5: Perform the Nucleophilic Substitution
When CN⁻ attacks the CH2 group, the chlorine atom leaves, and a new bond is formed between the carbon and the cyanide group (CN). The reaction can be summarized as follows:

4-bromobenzyl chloride + NaCN → 4-bromobenzyl cyanide + NaCl

### Step 6: Write the Product Structure
The product formed is 4-bromobenzyl cyanide, which can be represented as:

```
Br
|
C6H4-CH2-CN
```

### Step 7: Name the Product
According to IUPAC naming conventions, the product is named 4-bromobenzyl cyanide.

### Conclusion
The correct answer to the question is option 1: **4-bromobenzyl cyanide**.

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