If the pressure of `H_2` (g) is increased from 1 atm to 100 atm keeping [`H^+`] constant at `1M`, the change in reduction potential of hydrogen half cell at 25°C will be :-

Options

A. 0.059 V
B. `-0.059 V`
C. 00.0295 V
D. 0.118 V

Answer

B

Explanation

`H^+ +e^(-) to 1/2H_2" "E^@=0`
`E= E^@-(0.0591)/1log(P_H)^(1//2)=0-(0.0591)/1 log(100)^(1//2)`
`=0.591 V`